9c^2-10c+1=0

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Solution for 9c^2-10c+1=0 equation:


Simplifying
9c2 + -10c + 1 = 0

Reorder the terms:
1 + -10c + 9c2 = 0

Solving
1 + -10c + 9c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -9c)(1 + -1c) = 0

Subproblem 1

Set the factor '(1 + -9c)' equal to zero and attempt to solve: Simplifying 1 + -9c = 0 Solving 1 + -9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -9c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -9c = 0 + -1 -9c = 0 + -1 Combine like terms: 0 + -1 = -1 -9c = -1 Divide each side by '-9'. c = 0.1111111111 Simplifying c = 0.1111111111

Subproblem 2

Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1

Solution

c = {0.1111111111, 1}

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